3x^2-78x+75=0

Solution for 3x^2-78x+75=0 equation:

3x^2-78x+75=0

a = 3; b = -78; c = +75;
Δ = b2-4ac
Δ = -782-4·3·75
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-78)-72}{2*3}=\frac{6}{6}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-78)+72}{2*3}=\frac{150}{6}
=25
$